Integrand size = 10, antiderivative size = 64 \[ \int \frac {\text {sech}^{-1}(a x)^2}{x} \, dx=\frac {1}{3} \text {sech}^{-1}(a x)^3-\text {sech}^{-1}(a x)^2 \log \left (1+e^{2 \text {sech}^{-1}(a x)}\right )-\text {sech}^{-1}(a x) \operatorname {PolyLog}\left (2,-e^{2 \text {sech}^{-1}(a x)}\right )+\frac {1}{2} \operatorname {PolyLog}\left (3,-e^{2 \text {sech}^{-1}(a x)}\right ) \]
1/3*arcsech(a*x)^3-arcsech(a*x)^2*ln(1+(1/a/x+(1/a/x-1)^(1/2)*(1+1/a/x)^(1 /2))^2)-arcsech(a*x)*polylog(2,-(1/a/x+(1/a/x-1)^(1/2)*(1+1/a/x)^(1/2))^2) +1/2*polylog(3,-(1/a/x+(1/a/x-1)^(1/2)*(1+1/a/x)^(1/2))^2)
Time = 0.04 (sec) , antiderivative size = 63, normalized size of antiderivative = 0.98 \[ \int \frac {\text {sech}^{-1}(a x)^2}{x} \, dx=-\frac {1}{3} \text {sech}^{-1}(a x)^3-\text {sech}^{-1}(a x)^2 \log \left (1+e^{-2 \text {sech}^{-1}(a x)}\right )+\text {sech}^{-1}(a x) \operatorname {PolyLog}\left (2,-e^{-2 \text {sech}^{-1}(a x)}\right )+\frac {1}{2} \operatorname {PolyLog}\left (3,-e^{-2 \text {sech}^{-1}(a x)}\right ) \]
-1/3*ArcSech[a*x]^3 - ArcSech[a*x]^2*Log[1 + E^(-2*ArcSech[a*x])] + ArcSec h[a*x]*PolyLog[2, -E^(-2*ArcSech[a*x])] + PolyLog[3, -E^(-2*ArcSech[a*x])] /2
Result contains complex when optimal does not.
Time = 0.46 (sec) , antiderivative size = 79, normalized size of antiderivative = 1.23, number of steps used = 9, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.800, Rules used = {6839, 3042, 26, 4201, 2620, 3011, 2720, 7143}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\text {sech}^{-1}(a x)^2}{x} \, dx\) |
\(\Big \downarrow \) 6839 |
\(\displaystyle -\int \sqrt {\frac {1-a x}{a x+1}} (a x+1) \text {sech}^{-1}(a x)^2d\text {sech}^{-1}(a x)\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle -\int -i \text {sech}^{-1}(a x)^2 \tan \left (i \text {sech}^{-1}(a x)\right )d\text {sech}^{-1}(a x)\) |
\(\Big \downarrow \) 26 |
\(\displaystyle i \int \text {sech}^{-1}(a x)^2 \tan \left (i \text {sech}^{-1}(a x)\right )d\text {sech}^{-1}(a x)\) |
\(\Big \downarrow \) 4201 |
\(\displaystyle i \left (2 i \int \frac {e^{2 \text {sech}^{-1}(a x)} \text {sech}^{-1}(a x)^2}{1+e^{2 \text {sech}^{-1}(a x)}}d\text {sech}^{-1}(a x)-\frac {1}{3} i \text {sech}^{-1}(a x)^3\right )\) |
\(\Big \downarrow \) 2620 |
\(\displaystyle i \left (2 i \left (\frac {1}{2} \text {sech}^{-1}(a x)^2 \log \left (e^{2 \text {sech}^{-1}(a x)}+1\right )-\int \text {sech}^{-1}(a x) \log \left (1+e^{2 \text {sech}^{-1}(a x)}\right )d\text {sech}^{-1}(a x)\right )-\frac {1}{3} i \text {sech}^{-1}(a x)^3\right )\) |
\(\Big \downarrow \) 3011 |
\(\displaystyle i \left (2 i \left (-\frac {1}{2} \int \operatorname {PolyLog}\left (2,-e^{2 \text {sech}^{-1}(a x)}\right )d\text {sech}^{-1}(a x)+\frac {1}{2} \text {sech}^{-1}(a x) \operatorname {PolyLog}\left (2,-e^{2 \text {sech}^{-1}(a x)}\right )+\frac {1}{2} \text {sech}^{-1}(a x)^2 \log \left (e^{2 \text {sech}^{-1}(a x)}+1\right )\right )-\frac {1}{3} i \text {sech}^{-1}(a x)^3\right )\) |
\(\Big \downarrow \) 2720 |
\(\displaystyle i \left (2 i \left (-\frac {1}{4} \int e^{-2 \text {sech}^{-1}(a x)} \operatorname {PolyLog}\left (2,-e^{2 \text {sech}^{-1}(a x)}\right )de^{2 \text {sech}^{-1}(a x)}+\frac {1}{2} \text {sech}^{-1}(a x) \operatorname {PolyLog}\left (2,-e^{2 \text {sech}^{-1}(a x)}\right )+\frac {1}{2} \text {sech}^{-1}(a x)^2 \log \left (e^{2 \text {sech}^{-1}(a x)}+1\right )\right )-\frac {1}{3} i \text {sech}^{-1}(a x)^3\right )\) |
\(\Big \downarrow \) 7143 |
\(\displaystyle i \left (2 i \left (\frac {1}{2} \text {sech}^{-1}(a x) \operatorname {PolyLog}\left (2,-e^{2 \text {sech}^{-1}(a x)}\right )-\frac {1}{4} \operatorname {PolyLog}\left (3,-e^{2 \text {sech}^{-1}(a x)}\right )+\frac {1}{2} \text {sech}^{-1}(a x)^2 \log \left (e^{2 \text {sech}^{-1}(a x)}+1\right )\right )-\frac {1}{3} i \text {sech}^{-1}(a x)^3\right )\) |
I*((-1/3*I)*ArcSech[a*x]^3 + (2*I)*((ArcSech[a*x]^2*Log[1 + E^(2*ArcSech[a *x])])/2 + (ArcSech[a*x]*PolyLog[2, -E^(2*ArcSech[a*x])])/2 - PolyLog[3, - E^(2*ArcSech[a*x])]/4))
3.1.6.3.1 Defintions of rubi rules used
Int[(Complex[0, a_])*(Fx_), x_Symbol] :> Simp[(Complex[Identity[0], a]) I nt[Fx, x], x] /; FreeQ[a, x] && EqQ[a^2, 1]
Int[(((F_)^((g_.)*((e_.) + (f_.)*(x_))))^(n_.)*((c_.) + (d_.)*(x_))^(m_.))/ ((a_) + (b_.)*((F_)^((g_.)*((e_.) + (f_.)*(x_))))^(n_.)), x_Symbol] :> Simp [((c + d*x)^m/(b*f*g*n*Log[F]))*Log[1 + b*((F^(g*(e + f*x)))^n/a)], x] - Si mp[d*(m/(b*f*g*n*Log[F])) Int[(c + d*x)^(m - 1)*Log[1 + b*((F^(g*(e + f*x )))^n/a)], x], x] /; FreeQ[{F, a, b, c, d, e, f, g, n}, x] && IGtQ[m, 0]
Int[u_, x_Symbol] :> With[{v = FunctionOfExponential[u, x]}, Simp[v/D[v, x] Subst[Int[FunctionOfExponentialFunction[u, x]/x, x], x, v], x]] /; Funct ionOfExponentialQ[u, x] && !MatchQ[u, (w_)*((a_.)*(v_)^(n_))^(m_) /; FreeQ [{a, m, n}, x] && IntegerQ[m*n]] && !MatchQ[u, E^((c_.)*((a_.) + (b_.)*x)) *(F_)[v_] /; FreeQ[{a, b, c}, x] && InverseFunctionQ[F[x]]]
Int[Log[1 + (e_.)*((F_)^((c_.)*((a_.) + (b_.)*(x_))))^(n_.)]*((f_.) + (g_.) *(x_))^(m_.), x_Symbol] :> Simp[(-(f + g*x)^m)*(PolyLog[2, (-e)*(F^(c*(a + b*x)))^n]/(b*c*n*Log[F])), x] + Simp[g*(m/(b*c*n*Log[F])) Int[(f + g*x)^( m - 1)*PolyLog[2, (-e)*(F^(c*(a + b*x)))^n], x], x] /; FreeQ[{F, a, b, c, e , f, g, n}, x] && GtQ[m, 0]
Int[((c_.) + (d_.)*(x_))^(m_.)*tan[(e_.) + (Complex[0, fz_])*(f_.)*(x_)], x _Symbol] :> Simp[(-I)*((c + d*x)^(m + 1)/(d*(m + 1))), x] + Simp[2*I Int[ (c + d*x)^m*(E^(2*((-I)*e + f*fz*x))/(1 + E^(2*((-I)*e + f*fz*x)))), x], x] /; FreeQ[{c, d, e, f, fz}, x] && IGtQ[m, 0]
Int[((a_.) + ArcSech[(c_.)*(x_)]*(b_.))^(n_)*(x_)^(m_.), x_Symbol] :> Simp[ -(c^(m + 1))^(-1) Subst[Int[(a + b*x)^n*Sech[x]^(m + 1)*Tanh[x], x], x, A rcSech[c*x]], x] /; FreeQ[{a, b, c}, x] && IntegerQ[n] && IntegerQ[m] && (G tQ[n, 0] || LtQ[m, -1])
Int[PolyLog[n_, (c_.)*((a_.) + (b_.)*(x_))^(p_.)]/((d_.) + (e_.)*(x_)), x_S ymbol] :> Simp[PolyLog[n + 1, c*(a + b*x)^p]/(e*p), x] /; FreeQ[{a, b, c, d , e, n, p}, x] && EqQ[b*d, a*e]
Time = 0.26 (sec) , antiderivative size = 136, normalized size of antiderivative = 2.12
method | result | size |
derivativedivides | \(\frac {\operatorname {arcsech}\left (a x \right )^{3}}{3}-\operatorname {arcsech}\left (a x \right )^{2} \ln \left (1+\left (\frac {1}{a x}+\sqrt {\frac {1}{a x}-1}\, \sqrt {1+\frac {1}{a x}}\right )^{2}\right )-\operatorname {arcsech}\left (a x \right ) \operatorname {polylog}\left (2, -\left (\frac {1}{a x}+\sqrt {\frac {1}{a x}-1}\, \sqrt {1+\frac {1}{a x}}\right )^{2}\right )+\frac {\operatorname {polylog}\left (3, -\left (\frac {1}{a x}+\sqrt {\frac {1}{a x}-1}\, \sqrt {1+\frac {1}{a x}}\right )^{2}\right )}{2}\) | \(136\) |
default | \(\frac {\operatorname {arcsech}\left (a x \right )^{3}}{3}-\operatorname {arcsech}\left (a x \right )^{2} \ln \left (1+\left (\frac {1}{a x}+\sqrt {\frac {1}{a x}-1}\, \sqrt {1+\frac {1}{a x}}\right )^{2}\right )-\operatorname {arcsech}\left (a x \right ) \operatorname {polylog}\left (2, -\left (\frac {1}{a x}+\sqrt {\frac {1}{a x}-1}\, \sqrt {1+\frac {1}{a x}}\right )^{2}\right )+\frac {\operatorname {polylog}\left (3, -\left (\frac {1}{a x}+\sqrt {\frac {1}{a x}-1}\, \sqrt {1+\frac {1}{a x}}\right )^{2}\right )}{2}\) | \(136\) |
1/3*arcsech(a*x)^3-arcsech(a*x)^2*ln(1+(1/a/x+(1/a/x-1)^(1/2)*(1+1/a/x)^(1 /2))^2)-arcsech(a*x)*polylog(2,-(1/a/x+(1/a/x-1)^(1/2)*(1+1/a/x)^(1/2))^2) +1/2*polylog(3,-(1/a/x+(1/a/x-1)^(1/2)*(1+1/a/x)^(1/2))^2)
\[ \int \frac {\text {sech}^{-1}(a x)^2}{x} \, dx=\int { \frac {\operatorname {arsech}\left (a x\right )^{2}}{x} \,d x } \]
\[ \int \frac {\text {sech}^{-1}(a x)^2}{x} \, dx=\int \frac {\operatorname {asech}^{2}{\left (a x \right )}}{x}\, dx \]
\[ \int \frac {\text {sech}^{-1}(a x)^2}{x} \, dx=\int { \frac {\operatorname {arsech}\left (a x\right )^{2}}{x} \,d x } \]
\[ \int \frac {\text {sech}^{-1}(a x)^2}{x} \, dx=\int { \frac {\operatorname {arsech}\left (a x\right )^{2}}{x} \,d x } \]
Timed out. \[ \int \frac {\text {sech}^{-1}(a x)^2}{x} \, dx=\int \frac {{\mathrm {acosh}\left (\frac {1}{a\,x}\right )}^2}{x} \,d x \]